Question

I have an application with a Listbox with files and a menu. When I right-click an item from my listbox I have a menu for example Send. When I press ‘Send’ I want another window to open (I already have the new window) and in the new window I want to have the item-path that I selected (I have this path in the main window).

private void MenuItemSend_Click(object sender, RoutedEventArgs e) 
{             
    if (listBoxFiles.SelectedIndex == -1) 
    { 
        return; 
    } 

    string filePath = (listBoxFiles.SelectedItem).ToString(); --- my file path
    StatisticsWindow sForm = new StatisticsWindow();
    sForm.ShowDialog(); -- open the new window
} 

How can I do it ?

Thanks

Answer 1

Why don’t you create a constructor for the window?

Instead of

new IpStatisticsWindow();

this:

new IpStatisticsWindow(filePath);

// In the IpStatisticsWindow class
public IpStatisticsWindow(string path)
{
    //do something with path
}

You could of course also create a property or a method which handles it, then you can pass it there, e.g.

IPsForm.Path = filePath;
IPsForm.HandlePath(filePath);