i have an argb value in the parameter of a function and the function needs to get rid of the agb values and only keep the r. How would you do that? thank-you
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i have an argb value in the parameter of a function and the function needs to get rid of the agb values and only keep the r. How would you do that? thank-you
That is done with bitwise shifting and bitwise AND.
The uint in a 32 bit integer. Each of the A,R,G,B takes up 8 of its bits(one byte).
And they appear I the same order as the name implies A,R,G,B
To get out b you just need to mask out all the other bits with a bitwise AND statement.
a=argb&255
because 255 in binary is 11111111, it only keeps the needed bits.
for g you first need to shift the bits then do the above.
g=argb>>8&255
r is same but shift 16 bits
r=argb>>16&255
and a
a=argb>>24&255
Hope that helps