Question

I have an array

a[]= {34,45,65,55,67}

I need C or TCL code to build a new array with the each element repeated ‘N’ times.

For example when n=2 , resultant array should be

b[]= {34,34,45,45,65,65,55,55,67,67}

similarly when n=3, array should be

b[]={34,34,34,45,45,45,65,65,65,55,55,55,67,67,67}

How can i do this ???

Answer 1

// Input parameters
int i,j;
int a[] = {34,45,65,55,67};
int aSize = 5;
int repeat = 10;

// Create a new array with a dynamic size.
// This array must be freed after to avoid memory leaks
int b* = (int*) malloc(sizeof(int) * aSize * repeat);

for (i = 0; i < aSize; ++i) // for all elements in a
    for (j = 0; j < repeat; ++j) // repeat them "repeat" times
        b[i * repeat + j] = a[i];  // i * repeat + j is the current element in b

// do something with b here

// release memory
free(b);