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Home/ Questions/Q 751139
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:37:56+00:00 2026-05-14T14:37:56+00:00

I have an array being returned from the database that looks like so: $data

  • 0

I have an array being returned from the database that looks like so:

$data = array(201 => array('description' => blah, 'hours' => 0),
              222 => array('description' => feh, 'hours' => 0);

In the next bit of code, I’m using a foreach and checking the for the key in another table. If the next query returns data, I want to update the ‘hours’ value in that key’s array with a new hours value:

foreach ($data as $row => $value){
   $query = $db->query('SELECT * FROM t WHERE id=$row');
   if ($result){
      $value['hours'] = $result['hours'];
   }

It’s all fine except that I’ve tried just about every combination of declarations for the foreach loop, but I keep getting the error that the $value['hours'] is an invalid reference. I’ve tried declaring $value[] … but that doesn’t work either. I don’t need to iterate through $value so another foreach loop isn’t necessary.

Surely this is easier than my brain is perceiving it.

Here’s the whole snippet:

foreach($_gspec as $key => $value){

            $sql = sprintf('SELECT * FROM List WHERE specialtyID=%s', $key);
            $query = $db->query($sql);

            if ($query->num_rows() !== 0){

                $result = $query->row_array();
                $value['hours'] = $result['hours'];

            }
        }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:37:56+00:00Added an answer on May 14, 2026 at 2:37 pm

    You want

    $data[$row]['hours'] = $result['hours']

    $row would be better named as $key (that is what it is!)

    Some people would suggest using pointers, but I find this way makes more sense to me.

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