Question

I have an array called $friend_array. When I print_r($friend_array) it looks like this:

Array ( [0] => 3,2,5 ) 

I also have a variable called $uid that is being pulled from the url.

On the page I’m testing, $uid has a value of 3 so it is in the array.

However, the following is saying that it isn’t there:

if(in_array($uid, $friend_array)){
  $is_friend = true;
}else{
  $is_friend = false;

This always returns false. I echo the $uid and it is 3. I print the array and 3 is there.

What am I doing wrong? Any help would be greatly appreciated!

Answer 1

Array ( [0] => 3,2,5 ) means that the array element 0 is a string 3,2,5, so, before you do an is_array check for the $uid so you have to first break that string into an array using , as a separator and then check for$uid:

// $friend_array contains as its first element a string that
// you want to make into the "real" friend array:
$friend_array = explode(',', $friend_array[0]);

if(in_array($uid, $friend_array)){
  $is_friend = true;
}else{
  $is_friend = false;
}

Working example