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Home/ Questions/Q 7162495
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:44:41+00:00 2026-05-28T13:44:41+00:00

I have an array containing strings with prices and sometimes surrounded by characters. How

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I have an array containing strings with prices and sometimes surrounded by characters.

How do I transform it from?

[0] > '$9.99/aa'
[1] > '$2.99'
[2] > '$1.'

to:

[0] > '9.99'
[1] > '2.99'
[2] > '1'

So I can do comparisons with the values? I just need to know how to change one and I can apply it to the array easily

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:44:41+00:00Added an answer on May 28, 2026 at 1:44 pm
    +myString.replace(/[^\d.ex-]+/gi, '')
    

    strips out all characters that cannot appear in a JavaScript number, and then applies the + operator to it to convert it to a number. If you don’t have numbers in hex format or exponential format then you can do without the ex.

    EDIT:

    To handle locales, and handle numbers in a more tailored way, I would do the following

    // Get rid of myriad separators and normalize the fraction separator.
    if ((0.5).toLocaleString().indexOf(',') >= 0) {
      myString = myString.replace(/\./g, '').replace(/,/g, '.');
    } else {
      myString = myString.replace(/,/g, '');
    }
    
    var numericValue = +(myString.match(
        // Matches JavaScript number literals excluding octal.
        /[+-]?(?:(?:(?:0|[1-9]\d*)(?:\.\d*)?|\.\d+)(?:e[+-]?\d+)?|0x[0-9a-f]+)/i)
        // Will produce NaN if there's no match.
        || NaN);
    
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