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Home/ Questions/Q 6096423
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:55:32+00:00 2026-05-23T12:55:32+00:00

I have an array d = [‘foo’, ‘bar’, ‘baz’] , and want to put

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I have an array d = ['foo', 'bar', 'baz'], and want to put its elements together into a string delimited by , and and at the last element so that it will become foo, bar and baz.

Here is what I’m trying to do:

s = ''
d.each_with_index { |x,i|
  s << x
  s << i < d.length - 1? i == d.length - 2 ? ' and ' : ', ' : ''
}

but the interpreter gives an error:

`<': comparison of String with 2 failed (ArgumentError)

However, it works with += instead of <<, but the Ruby Cookbook says that:

If efficiency is important to you, don’t build a new string when you can append items onto an existing string. [And so on]… Use str << var1 << ' ' << var2 instead.

Is it possible without += in this case?

Also, there has to be a more elegant way of doing this than the code above.

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:55:32+00:00Added an answer on May 23, 2026 at 12:55 pm

    You’re just missing some parenthesis:

        d = ['foo', 'bar', 'baz']
        s = ''
        d.each_with_index { |x,i|
          s << x
          s << (i < d.length - 1? (i == d.length - 2 ? ' and ' : ', ') : '')
        }
    
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