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Home/ Questions/Q 4266410
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T06:45:24+00:00 2026-05-21T06:45:24+00:00

I have an array declared as Object array[N]; and a function as void GetArray(void**

  • 0

I have an array declared as

Object array[N];

and a function as

void GetArray(void** array, size_t count)
{
    *array = array;
    *count = N;
}

I’m trying to call the function with this code:

size_t number;
GetArray(XXX, &number);

where is XXX what should I pass to get the array? Thank you

EDIT 1

Object *array
GetArray((void**)array, number)

EDIT 2

static Object array[N]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T06:45:24+00:00Added an answer on May 21, 2026 at 6:45 am

    Though I’m not 100% convinced that I understand your intent correctly,
    if GetArray has to return Object array[N] itself, how about returning
    Object* from GetArray?
    For example:

    size_t const N = 1;
    Object array[N];
    
    Object* GetArray(size_t* count)
    {
        *count = N;
        return array;
    }
    

    EDIT:
    As far as I see your edited question, the argument number for GetArray
    seems to be taken as a reference(not pointer).
    So, as for the array too, how about taking a reference instead of a pointer?
    Then you can avoid the troublesome void** stuff.
    For example:

    void GetArray(Object*& arr, size_t& count)
    {
        arr = array;
        count = N;
    }
    
    int main() {
        size_t number;
        Object *arr;
        GetArray(arr, number);
        for ( size_t i = 0; i < number; ++ i ) {
            Object o = arr[i]; // example
        }
    }
    
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