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Home/ Questions/Q 6527997
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T09:29:37+00:00 2026-05-25T09:29:37+00:00

I have an array like this: $elements = array( array(name => Paco, group =>

  • 0

I have an array like this:

$elements = array(
    array("name" => "Paco", "group" => 2),
    array("name" => "Juan", "group" => 3),
    array("name" => "Marta", "group" => 2),
    array("name" => "Julia", "group" => 4),
    array("name" => "Silvia", "group" => 2)
);

I need to avoid repeating the group. If there are several elements with the same group, the final array must have only the first of each group:

$elements = array(
    array("name" => "Paco", "group" => 2),
    array("name" => "Juan", "group" => 3),
    array("name" => "Julia", "group" => 4)
);

Is there a better way than foreaching the array and processing each row? Something like GROUP BY in SQL?

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  1. Editorial Team
    Editorial Team
    2026-05-25T09:29:37+00:00Added an answer on May 25, 2026 at 9:29 am

    Seeing as a lot of strange code has come up, some are wildly inefficient or just strange in my opinion:

    $values = array(); 
    
    foreach($elements as $element) { 
        if (!isset($values[$element['group']])) {
            $values[$element['group']] = $element; 
        }
    } 
    

    And what you should have now is an array where only the FIRST occurence of a group is saved and only requires one pass, O(N). If you don’t want the index to be the group id then just do:

    $values2 = array_values($values);
    

    PS. If you really dislike array_values(), then you could also do it like this (or some variation of this):

    $values = array();
    $groupkeys = array();
    
    foreach($elements as $element) { 
        if (!isset($groupkeys[$element['group']])) {
             $values[] = $element;
             $groupkeys[$element['group']] = TRUE;
        } 
    }
    
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