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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T15:48:42+00:00 2026-06-18T15:48:42+00:00

I have an array like this: unsigned char arr[] = {0x55}; unsigned char byte

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I have an array like this:

   unsigned char arr[] = {0x55}; 
   unsigned char byte = arr[0];

And I want to have byte be the hex representation, just like it is in the array.
But when I look at it in gdb, I keep getting that byte is 85 ‘U’. What has happened? Why don’t I see 0x55, or even the binary representation 110111?

Thanks for any help!

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  1. Editorial Team
    Editorial Team
    2026-06-18T15:48:43+00:00Added an answer on June 18, 2026 at 3:48 pm

    Use p/x byte to look at it. gdb defaults to printing decimal unless you tell it otherwise. You get the 'U' because that’s also part of the default for printing char type variables.

    The value stored in the variable is binary – it’s only how you’re looking at it that is confusing you, I think. 0x55, 85, and 'U' are all different ways to interpret the same data.

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