Question

I have an array of 100 numbers and I only gave the array even values. How can I print out how many elements of the array I have to add to obtain a sum < than 1768 using a WHILE LOOP? The following is what I have so far and I am stuck… thanks in advance for the help

void setup() {

  int[] x = new int[100];
  int i=0;
  int sum=0;

  for(i=0; i<100; i++) {
    if (i%2==0) {
      x[i]=i;
      sum+=x[i];
    }
  }
}

Answer 1

 void setup() {
     int i = 0;
     int sum = 0;
     int counter = 0;

     while (sum < 1768) {
         sum += i;
         i += 2;
         counter++;
     }

     System.out.println(counter);
 }

You start with the even index of 0. Then just skip odd numbers by using i += 2.
If the number of elements is limited with 100, add i < 200 to the while condition:

while (sum < 1768 && i < 200)

_{The array of 100 even numbers will contain numbers from 0 to 200.}

The variable counter will contain the number of additions performed. Its value will be equal to i / 2, so you can remove that additional variable.