Question

I have an array of array of hashes which can be nested any level deep.

array = [
    [ ['a','2'],  ['b','5'] ], 
    [ ['c','4'], ['d','5']  ],  
    [ ['e','6'], [f,7] ],
    ...]

In the first stage I need to compare each consecutive hash – keep one of the elements and discarding the other.
In the second step the selected element of hash 1 have to be compared to selected element of the hash 2. This process has to continue till i am left with just one hashed element.

How do i do this i Ruby ?

thanks a lot for answering

Answer 1

You can do this with ==:

array1 = [
    [ ['a','2'],  ['b','5'] ], 
    [ ['c','4'], ['d','5']  ],  
    [ ['e','6'], ['f',7] ]
    ]
array2 = [
    [ ['a','2'],  ['b','5'] ], 
    [ ['c','4'], ['d','5']  ],  
    [ ['e','6'], ['f',7] ]
    ]
array3 = [
    [ ['not','equal'] ]
    ]

array1 == array2
# => true

array2 == array3
# => false

See Array#== for specifics.