Question

I have an array of chars like this one:

char arr[3]="hi";
cout << arr;// this will print out hi

So is the operator<< has an overloaded version that takes an ostream object and char *. so cout<<arr; first arr will decays to a chat * . and then operator<<() will print out what the char pointer is pointing to until it find a null-character ?

The same question for cin>>arr; how does it work with operator>> that takes an array as the second operand.

Answer 1

Your ostream and istream do have operator<< and operator>> overloaded to take a char*, and arrays decay into pointers to the first element. So, yes it does what you say it does.