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Home/ Questions/Q 6387643
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T03:10:38+00:00 2026-05-25T03:10:38+00:00

I have an array of images and then I iterate through each using $.each

  • 0

I have an array of images and then I iterate through each using $.each but I can’t get the images to show on the page, it ends up with nothing getting showed.

<ul id="imagesList">
  <li>No images found</li>
</ul>

$(function(){
            //load image array
            var images = {'image1':'assets/img/linkedin_30px.png','image2':'assets/img/twitter_30px.png'};
            $.each(images, function(){
               $('#imagesList').appendTo('<li>' + this + '</li>'); 
            });
        });
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:10:39+00:00Added an answer on May 25, 2026 at 3:10 am

    You are using appendTo instead of append. Use append:

    $.each(images, function(){
        $('#imagesList').append('<li><img src="' + this + '" /></li>'); 
    });
    

    Or, if you insist on using appendTo:

    $.each(images, function(){
        $('<li><img src="' + this + '" /></li>').appendTo('#imagesList'); 
    });
    

    If you want to show a loader while the image is loading, use this:

    var $list = $('#imagesList');
    
    $.each(images, function(i, src) {
        var $li = $('<li class="loading">').appendTo($list);
    
        $('<img>').appendTo($li).one('load', function() {
            $li.removeClass('loading');
        }).attr('src', src);
    });
    

    Here’s the fiddle: http://jsfiddle.net/fyar1u7a/1/

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