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Home/ Questions/Q 1091919
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T23:36:23+00:00 2026-05-16T23:36:23+00:00

I have an array of lines each defined by 2 points. I am working

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I have an array of “lines” each defined by 2 points. I am working with only the line segments lying between those points. I need to search lines that could continue one another (relative to some angle) and lie on the same line (with some offset)

I mean I had something like 3 lines

alt text

I solved some mathematical problem (formulation of which is my question) and got understanding that there are lines that could be called relatively one line (with some angle K and offset J)

alt text

And of course by math formulation I meant some kind of math formula like

alt text

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  1. Editorial Team
    Editorial Team
    2026-05-16T23:36:23+00:00Added an answer on May 16, 2026 at 11:36 pm
    1. Sort all your segments based on angle (in range 0 to Pi), and build a sorted map of angle-to-segment.
    2. Decide on some angle difference threshold below which two segments can be considered parallel. Iterate through your map and for each mapping, consider adjacent mappings on either side of the angle (needs wrap around) which are considered parallel.
    3. Within each set of nearly-parallel segments, see if they are “continuations” of each other.

    Two segments (A,B) and (C,D) are roughly collinear if all possible pairings of the 4 points are roughly parallel. You can use the same test as above.

    Pseudo-code:

    Angle(A,B)
        return Atan((B.y-A.y) / (B.x-A.x)) // use atan2 if possible, but needs wrapping
    
    NearlyParallel(angle1, angle2)
        delta = Abs(angle1-angle2)
        return (delta < threshold) or (delta > Pi-threshold)
    
    Collinear(A,B, C,D)
        // Assume NearlyParallel(Angle(A,B), Angle(C,D)) == true
        return NearlyParallel(Angle(A,C), Angle(B,D)) and NearlyParallel(Angle(A,D), Angle(B,C))
    
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