Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4060184
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T15:18:21+00:00 2026-05-20T15:18:21+00:00

I have an array of numbers and I’d like to create another array that

  • 0

I have an array of numbers and I’d like to create another array that represents the rank of each item in the first array. I’m using Python and NumPy.

For example:

array = [4,2,7,1]
ranks = [2,1,3,0]

Here’s the best method I’ve come up with:

array = numpy.array([4,2,7,1])
temp = array.argsort()
ranks = numpy.arange(len(array))[temp.argsort()]

Are there any better/faster methods that avoid sorting the array twice?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T15:18:21+00:00Added an answer on May 20, 2026 at 3:18 pm

    Use advanced indexing on the left-hand side in the last step:

    array = numpy.array([4,2,7,1])
    temp = array.argsort()
    ranks = numpy.empty_like(temp)
    ranks[temp] = numpy.arange(len(array))
    

    This avoids sorting twice by inverting the permutation in the last step.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have an array of numbers that potentially have up to 8 decimal places
Lets say I have an array numbers that contains the following values: int numbers
I have an array of numbers and would like to retrieve one of the
I have an array of numbers, like: [1, 4, 7, 1, 2, 1, 3,
I have an array of a few million numbers. double* const data = new
Lets say I have this array, int[] numbers = {1, 3, 4, 9, 2};
Imagine you have a large array of floating point numbers, of all kinds of
I have an array of numbers from 1 to 100 (both inclusive). The size
I have an array of numbers from 5 to 6.4 but the numbers are
I have an array of numbers: @numbers = 1,2,3,6,8,9,11,12,13,14,15,20 and I want to print

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.