Question

I have an array of objects:

Square sq[81];

I think it uses the default constructor to created each.

When I go though a for loop to initialize each, it calls the destructor for each Square object in the array.

for (int k=0; k<9; k++) {
   for(int j=0; j<9; j++) {
      sq[count++] = Square(k, j);
   }
}

When Square(k, j) is called, is it deleting the object in sq[] and creating a new one?

Answer 1

sq[count++] = Square(k, j);

When Square(k, j) is called, is it deleting the object in sq[] and creating a new one?

No.

Square(k, j) creates a new temporary object and = copies it into the old one. The temporary object is then destroyed as it is not longer required and goes out of scope.

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BTW, you’re not actually initialising anything in the loop (other than that temporary, I mean); you’re just assigning, after-the-fact.