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Home/ Questions/Q 8378629
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T15:58:17+00:00 2026-06-09T15:58:17+00:00

I have an array of objects. There is a getCountry() in the object. I

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I have an array of objects. There is a getCountry() in the object. I want to set a flag when the getCountry() is equal to say ‘XXX’.

As of know, I am doing,

boolean isXXX=false;
if(custAcctArray != null)
{
    for(int index=0;index<custAcctArray.length;index++)
    {
        if(custAcctArray[i].getCountry().equalsIgnoreCase("XXX"))
        {
            isXXX=true;
        }
    }
}

if(isXXX)
{
    Do something about it....
}

I somehow don’t like this logic when I assume the array is filled with some 100 or odd objects. Can someone throw or shed light at other ways of achieving the final output in an efficient way?
What I want: set a flag when getCountry() == “XXX“

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T15:58:18+00:00Added an answer on June 9, 2026 at 3:58 pm
    boolean isXXX=false;
    if(custAcctArray != null)
    {
        for(int index=0;index<custAcctArray.length;index++)
        {
            if(custAcctArray[i].getCountry().equalsIgnoreCase("XXX"))
            {
                isXXX=true;
                break;//<-------------you need to exit to be quick and true solution!!!!
            }
    }
    }
    
    if(isXXX)
    {
    Do something about it....
    }
    

    Do you see the break; ? This exits the big loop as soon as possible. If you dont, the next iteration could set it to other value.

    You can also use a “separate” array outside the object to access it quicker(1 less bounds checking)

    A better way: when setting the country values, check that if “xxx” then set isXXX rightaway without needing to use a “check” algortihm 🙂

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