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Home/ Questions/Q 8629011
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T08:41:43+00:00 2026-06-12T08:41:43+00:00

I have an array of objects with the following format: obj = { ref:

  • 0

I have an array of objects with the following format:

obj = { ref: 8, id: "obj-8" }

and a function which uses jQuery’s grep method to return an item from that array, by searching for the object ref property:

function returnObj(arr,r){
    return $.grep(arr, function(elem,index){ return elem.ref == r; })[0];
}

If I use this function on an array that has undefined elements in it (they were previously deleted using the delete operator), I get the following error: Uncaught TypeError: Cannot read property ‘ref’ of undefined, which I assume is thrown when an undefined element is encountered.

How can I modify the function so it doesn’t break?

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  1. Editorial Team
    Editorial Team
    2026-06-12T08:41:45+00:00Added an answer on June 12, 2026 at 8:41 am

    Just check to see if the current item is undefined, or simply “falsey” if you expect specifc objects, and return false if so.

    function returnObj(arr,r){
        return $.grep(arr, function(elem,index){ 
                               return elem ? elem.ref == r : false;
                           })[0];
    }
    

    Here’s another option. Since you’re using delete to remove the items, you can use the native .filter method, which skips over non-existent array members.

    function returnObj(arr,r){
        return arr.filter(function(elem){ elem.ref == r})[0];
    }
    
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