I have an array of pointers to Objective-C objects. These objects have a sort key associated with them. I’m trying to use qsort to sort the array of pointers to these objects. However, the first time my comparator is called, the first argument points to the first element in my array, but the second argument points to garbage, giving me an EXC_BAD_ACCESS when I try to access its sort key.
Here is my code (paraphrased):
- (void)foo:(int)numThingies {
Thingie **array;
array = malloc(sizeof(deck[0])*numThingies);
for(int i = 0; i < numThingies; i++) {
array[i] = [[Thingie alloc] initWithSortKey:(float)random()/RAND_MAX];
}
qsort(array[0], numThingies, sizeof(array[0]), thingieCmp);
}
int thingieCmp(const void *a, const void *b) {
const Thingie *ia = (const Thingie *)a;
const Thingie *ib = (const Thingie *)b;
if (ia.sortKey > ib.sortKey) return 1; //ib point to garbage, so ib.sortKey produces the EXC_BAD_ACCESS
else return -1;
}
Any ideas why this is happening?
The problem is two fold:
the first argument to qsort needs to be a pointer to the beginning of the array
the arguments passed to your sort function are actually pointers to the pointers of your data
Consider this working code:
Note that the comparison function resolves the data pointers by
NSObject *aO = *(NSObject **)aand theqsortfunction takesarrayas an argument directly.All of this, though, begs the question of Why bother?
NSArrayis very good at holding arrays of objects and is quite conveniently sortable. Performance is excellent in the general case. If performance analysis indicates that it isn’t, you can optimize it away relatively easily.Note, also, that I have been consistent in use of
sizeof()— same type in both places. Also, theconstin your original code is not necessary.