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Home/ Questions/Q 7166659
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:26:58+00:00 2026-05-28T14:26:58+00:00

I have an array of strings in jQuery. I have another array of keywords

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I have an array of strings in jQuery. I have another array of keywords that I want to use to filter the string array.

My two arrays:

    var arr = new Array("Sally works at Taco Bell", "Tom drives a red car", "Tom is from Ohio", "Alex is from Ohio");

    var keywords = new Array("Tom", "Ohio");

How can I filter the arr array using the keywords array in jQuery? In this situation it would filter out “Sally works at Taco Bell” and keep the rest.

Below is the actual code I am using.

var keywords= [];
var interval = "";
var pointer = '';
var scroll = document.getElementById("tail_print");

$("#filter_button").click(
function(){
    var id = $("#filter_box").val(); 
    if(id == "--Text--" || id == ""){
        alert("Please enter text before searching.");
    }else{
        keywords.push(id);
        $("#keywords-row").append("<td><img src=\"images/delete.png\" class=\"delete_filter\" /> " + id + "</td>");
    }
}
);

$(".delete_filter").click(
function(){
   ($(this)).remove(); 
}
);

function startTail(){
clearInterval(interval);
interval = setInterval(
function(){
    $.getJSON("ajax.php?function=tail&pointer=" + pointer + "&nocache=" + new Date(),
        function(data){
            pointer = data.pointer;
            $("#tail_print").append(data.log);
            scroll.scrollTop = scroll.scrollHeight;
        });
}, 1000);
}

The whole purpose of this is to allow the user to filter log results. So the user performs an action that starts startTail() and $.getJSON() retrieves a JSON object that is built by a PHP function and prints the results. Works flawlessly. Now I want to give the user the option to filter the incoming tailing items. The user clicks a filter button and jQuery takes the filter text and adds it to the keywords array then the data.log from the JSON object is filtered using the keywords array and then appended to the screen.

I also have a delete filter function that isn’t working. Maybe someone can help me with that.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:26:58+00:00Added an answer on May 28, 2026 at 2:26 pm
    $.grep( arr, $.proxy(/./.test, new RegExp(keywords.join("|"))));
    

    without jQuery:

    arr.filter(/./.test.bind(new RegExp(keywords.join("|"))));
    
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