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Home/ Questions/Q 8704265
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:03:29+00:00 2026-06-13T03:03:29+00:00

I have an array of URLs, and an array of data that I’m pulling

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I have an array of URLs, and an array of data that I’m pulling externally. The URLs and the data correspond one to one perfectly. I try to do this:

for (var i = 0; i < children.length; i++) {
    urls.push(children[i].data.url); 
}

for (var i = 0; i < children.length; i++) { 
    $.ajax({
         url: DATA_SOURCE,
         dataType: "jsonp",
         success: function (data2) {                           
             console.log(urls[0]);
             console.log(urls[i]);
         }
    });                        
}

The first log always prints the first element of the urls array. I can change the number to any other valid index and it works. The second log however always prints undefined. I initially grabbed urls from within the second loop, but I took it out just in case it turned out to be an asynchronous error or something. urls is initialized to be an Array, not an Object. Taking the second log out of the success function (and into the main scope of the for loop) makes it perform as expected. I’d be happy to chalk it up to the ajax request screwing it up somehow, but then why does the first log perform as expected?

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:03:30+00:00Added an answer on June 13, 2026 at 3:03 am

    $.ajax is asynchronous, this means that when the callbacks (success) run, the loop has already finished running and it is now set to children.length

    Accessing urls[ i ], equals to urls[ children.length therefore is undefined.

    An easy fix for this, would be to create scopes for each iteration

    for (var i = 0; i < children.length; i++) { 
      (function( index ) {
        $.ajax({
           url: DATA_SOURCE,
           dataType: "jsonp",
           success: function (data2) {                           
             console.log(urls[ index ]);
            }
        }); 
      })( i );                       
    }
    
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