Question

I have an array of y-values that form a line. Additionally, I have an array with the same number of elements as the y-array of values ranging from 0 to 1. We’ll call this array ‘z’. I want to plot the array of y-values so that the color of each point corresponds with the z-value.

In gnuplot, you can do this using the ‘lc variable’:

plot ’data’ using 1:2:3 with points lc variable  

Using the advice from here: Matplotlib scatterplot; colour as a function of a third variable

, I was able to use a scatter plot, which did work:

import matplotlib as mpl  
import matplotlib.pyplot as plt  

plt.scatter(x, y, c=z, s=1, edgecolors='none', cmap=mpl.cm.jet)  
plt.colorbar()  
plt.show()  

Is there a way to do this with the plot method in matplotlib, similar to this?

plt.plot(x, y, c=z)

When I tried the above code, all of the lines just appeared black.

Answer 1

you can use scatter:

plt.scatter(range(len(y)), y, c=z, cmap=cm.hot)

here you have the ipython -pylab session:

In [27]: z = [0.3,0.4,0.5,0.6,0.7,0.2,0.3,0.4,0.5,0.8,0.9]

In [28]: y = [3, 7, 5, 6, 4, 8, 3, 4, 5, 2, 9]

In [29]: plt.scatter(range(len(y)), y, s=60, c=z, cmap=cm.hot)
Out[29]: <matplotlib.collections.PathCollection at 0x9ec8400>

If you want to use plot you can get the equivalent figure as above with (pycrust session):

>>> from matplotlib import pyplot as plt
>>> from matplotlib import cm
>>> y = [3,7,5,6,4,8,3,4,5,2,9]
>>> z = [0.3,0.4,0.5,0.6,0.7,0.2,0.3,0.4,0.5,0.8,0.9]
>>> for x, (v, c) in enumerate(zip(y,z)):
...      plt.plot(x,v,marker='o', color=cm.hot(c))
...      
[<matplotlib.lines.Line2D object at 0x0000000008C42518>]
[<matplotlib.lines.Line2D object at 0x0000000008C426D8>]
[<matplotlib.lines.Line2D object at 0x0000000008C42B38>]
[<matplotlib.lines.Line2D object at 0x0000000008C452B0>]
[<matplotlib.lines.Line2D object at 0x0000000008C45438>]
[<matplotlib.lines.Line2D object at 0x0000000008C45898>]
[<matplotlib.lines.Line2D object at 0x0000000008C45CF8>]
[<matplotlib.lines.Line2D object at 0x0000000008C48198>]
[<matplotlib.lines.Line2D object at 0x0000000008C485F8>]
[<matplotlib.lines.Line2D object at 0x0000000008C48A58>]
[<matplotlib.lines.Line2D object at 0x0000000008C4B1D0>]
>>> plt.show()
>>>