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Home/ Questions/Q 7668163
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T15:17:26+00:00 2026-05-31T15:17:26+00:00

i have an array (the hashmap in TCL), so the command parray dn yields

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i have an array (the hashmap in TCL), so the command parray dn yields the following

                 dn(1)  = 52638515
                 dn(11) = 324009
                 dn(12) = 257949
                 dn(13) = 298844
                 dn(14) = 442499
                 dn(15) = 417333
                 dn(2)  = 49807360
                 dn(3)  = 52848230
                 dn(4)  = 39845888
                 dn(5)  = 26633830 

so i want this to set it to another array which starts from 1 to length(dn) .. I have several entries in dn like the data above with missing indexes in between. Is there any built in array commands in tcl that does that???

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  1. Editorial Team
    Editorial Team
    2026-05-31T15:17:27+00:00Added an answer on May 31, 2026 at 3:17 pm

    I can’t think of an automatic command, but you could do something like the following:

    set result {}
    set index 0
    foreach key [lsort -integer [array keys dn]] {
        lappend result [incr index] $db($key)
    }
    array set newDn $result
    

    Or, if you have 8.6 and tcllib AND you’re glutton for punishment but amusement:

    set index 0
    array set newDn [struct::list flatten \
                        [::struct::list mapfor x \
                            [dict values [lsort -stride 2 -integer [array get dn]]] \
                            {list [incr index] $x}]]
    

    Though I’d argue that the first version is somewhat easier to follow 🙂

    If tcllib struct::list had a zip command, it would probably be a lot cleaner, since you could zip the sorted (on keys) values with iota 1-n.

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