Question

I have an array which contains sets of three similar named items; however, sometimes there’s only two items in a set and I want to call these out.

<?php
$items = array(
'reviewpitfighter-1.138x88.jpg',
'reviewpitfighter-2.138x88.jpg',
'reviewpopfulmailsegacd-1.138x92.jpg',
'reviewpopfulmailsegacd-2.138x76.jpg',
'reviewpopfulmailsegacd-3.138x97.jpg'
);
?>

You’ll note that there are two reviewpitfigher* items, and three reviewpopfulmailsegacd* items. I’ve started down a rabbit hole of loops and feel that there is something simple I’m just glossing over.

Answer 1

Here’s the solution I came up with, sorry it took so long to post.

foreach($images as $value){
    $lastItem = explode('-', $images[$count - 1]);
    $parts = explode('-', $value);
    if(preg_match('/^1/', $parts[1]) && $count != 0){
        if(preg_match('/^2/',$lastItem[1])){
            $imgurl = preg_replace('/^p?review/','',$lastItem[0]);
            $sql = 'SELECT field FROM table WHERE field = "' . $imgurl . '"';
            $result = $dbConn->FetchArray($dbConn->Query($sql), MYSQL_ASSOC);
            $array[$imgurl] = $result;
        }
    }
    $count++;
}

I get an array of all the images, then I check to see if I’m looking at the first image, if I am then I see if the last image I looked at was the second image. At this point I then call into the database to get some information to display a neatly messaged out put of what reviews are missing a third image. In the end $array contains this list which I can loop over.