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Home/ Questions/Q 565737
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:54:12+00:00 2026-05-13T12:54:12+00:00

I have an array with subjects and every subject has connected time. I want

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I have an array with subjects and every subject has connected time. I want to compare every subjects in the list. If there are two of the same subjects, I want to add the times of both subjects, and also want to delete the second subject information (subject-name and time).

But If I delete the item, the list become shorter, and I get an out-of-range-error. I tried to make the list shorter with using subjectlegth-1, but this also don’t work.

   ...
   subjectlegth = 8
   for x in range(subjectlength):
        for y in range(subjectlength):
            if subject[x] == subject[y]:
                if x != y:
                    #add
                    time[x] = time[x] + time[y]
                    #delete
                    del time[y]
                    del subject[y]
                    subjectlength = subjectlength - 1
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  1. Editorial Team
    Editorial Team
    2026-05-13T12:54:12+00:00Added an answer on May 13, 2026 at 12:54 pm

    Iterate backwards, if you can:

    for x in range(subjectlength - 1, -1, -1):
    

    and similarly for y.

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