Question

I have an asp.net gridview and a column that has digits e.g. 1234567, I want to show the last 4 digits like so xxx4567. Is this possible.

I am binding my gridview to a list of objects as below:

List<Details> objdet = Manager.Get_Details(ID);

             if (objdet!= null)
             {

                 gvDetails.DataSource = objdet;
                 gvDetails.DataBind();
             }

and in my grid i have this:

 <asp:GridView ID="gvDetails" runat="server" AllowPaging ="true" 
                AllowSorting ="true" AutoGenerateColumns="false" GridLines="None" CssClass="mGrid">
                <Columns>
                <asp:BoundField DataField="DetNumber" HeaderText="Number" ReadOnly="true" />
</Columns>
            </asp:GridView>

Answer 1

In your Details object, add another Property called something like NumberWithMask:

public const int NumberWithMaskLength = 4;

public string DetNumber { get; set; }

public string NumberWithMask
{
    get
    {
        if (!string.IsNullOrEmpty(DetNumber) && DetNumber.Length > NumberWithMaskLength)
        {
            return new string('x', DetNumber.Length - NumberWithMaskLength ) + DetNumber.Substring(DetNumber.Length - NumberWithMaskLength );
        }
        return string.Empty;
    }
} 

Then use the new field in the relevant BoundField:

<asp:BoundField DataField="NumberWithMask" HeaderText="Number" ReadOnly="true" />