Question

I have an Asp.Net MVC app using jqGrid. Can I send the Model that is used to populate a lot of my ui controls(checkboxes, radio buttons, etc) to the server(controler action method). I would like to send this Model to the server instead of reading ui control by ui control. Can this be done?

  var myGrid = jQuery("#list").jqGrid({
                    url: '/Data/GridData/',
                    datatype: 'json',
                    mtype: 'POST',
                    colNames: ['Year', 'Overall %'],
                    colModel: [
                                            { name: 'Year', index: 'Year', width: 80, align: 'center' },

                                            { name: 'overallHarvestPercent', index: 'overallHarvestPercent', width: 80, align: 'center'}],

                    postData: { contactId: jQuery('#contactId').val() },
                    pager: jQuery('#pager'),
                    rowNum: 10,
                    rowList: [5, 10, 20, 50],
                    sortname: 'id',
                    sortorder: "desc",
                    viewrecords: true,
                    imgpath: '',
                    caption: 'Harvest Data Results'
                });

Answer 1

Specify your Model as the data type for the Controller Action’s Parameter.

public ActionResult Index(MyModel model)
{
 // Do stuff 
}