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Home/ Questions/Q 8489639
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T21:52:59+00:00 2026-06-10T21:52:59+00:00

I have an AsyncTask. protected class InitTask extends AsyncTask<Context, Integer, String> { View eachLayout;

  • 0

I have an AsyncTask.

protected class InitTask extends AsyncTask<Context, Integer, String> {

        View eachLayout;

        @Override
        protected String doInBackground(Context... params) {

            try {
                myfunction();
            } catch (Exception e) {

                e.printStackTrace();

            }

            return null;
        }

        @Override
        protected void onPostExecute(String result) {

            super.onPostExecute(result);


        }

        /*
         * (non-Javadoc)
         * 
         * @see android.os.AsyncTask#onPreExecute()
         */
        @Override
        protected void onPreExecute() {
            super.onPreExecute();

            linearLayout.invalidate();
        }

        @Override
        protected void onProgressUpdate(Integer... values) {
            super.onProgressUpdate(values);

            linearLayout.addView(eachLayout, params);
            linearLayout.invalidate();
        }

        /*
         * (non-Javadoc)
         * 
         * @see android.os.AsyncTask#onCancelled()
         */
        @Override
        protected void onCancelled() {
            super.onCancelled();
        }

        public void redrawLayout(View linearLayout) {
            try {

                eachLayout = linearLayout;
                publishProgress();

            } catch (Exception e) {

                e.printStackTrace();

            }
        }

    }


private void myFunction() {
        LayoutInflater layoutInflater = (LayoutInflater) this
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        params = new LinearLayout.LayoutParams(
                newLinearLayout.getLayoutParams().width,
                newLinearLayout.getLayoutParams().height);

        for (int i = 0; i < list.size(); i++) {
            final View eachLayout = layoutInflater.inflate(R.layout.sample, null);
            //..........................
            eachLayout.invalidate();
            initTask.redrawLayout(eachLayout);
        }

    }


 params = new LinearLayout.LayoutParams(
                linearLayout.getLayoutParams().width,
                linearLayout.getLayoutParams().height);

It shows IllegalStateException at this line
linearLayout.addView(eachLayout, params); .(This child already has a parent).

I am tried linearLayout.removeAllViews() etc…But it does not work.

How to solve this?

Thanks in Advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T21:53:00+00:00Added an answer on June 10, 2026 at 9:53 pm

    Try following:

    @Override
        protected void onProgressUpdate(Integer... values) {
            super.onProgressUpdate(values);
    
           if( ((LinearLayout) eachLayout.getParent()) != null 
                    &&  eachLayout != null) {
                 ((LinearLayout) eachLayout.getParent()).removeView(eachLayout);
           }
    
            linearLayout.addView(eachLayout, params);
            linearLayout.invalidate();
        }
    
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