Question

I have an attendee list for an event. Attendees objects are keyed to Profile Objects.
Within the view I’m trying to append 3 lists to make up attendee_list.

Models.py

class Attendee(models.Model):
    created = models.DateTimeField(auto_now_add=True)
    modified = models.DateTimeField(auto_now=True)
    profile = models.ForeignKey(Profile)
    event = models.ForeignKey(Event)
    verified = models.BooleanField(default=False)
    from_user = models.BooleanField(default=False)

view.py

verified_attendees = [va.profile for va in Attendee.objects.filter(event=event, verified=True)]
unverified_attendees = [uva.profile for uva in Attendee.objects.filter(event=event, verified=False, from_user=True)
pending_attendees = [pa.profile for pa in Attendee.objects.filter(event=event, from_user=False, verified=False)]
attendee_list = ????

What I’d like to accomplish(template):

{% for attendee in attendees_list %}

...

Name            |       Status
--------------------------------------
Jon Doe         |       Pending
Annie Smith     |       Verified!
Abraham Snow    |       Confirm Yes/No?

How can I throw these 3 lists into one, and still check which list they belong to (whether in the view or template)? The reason why I want one list is because I will be sorting attendees alphabetically. Thanks for you suggestions in advance!

Answer 1

Why split in the first place when you could do:

attendees = [(a.profile, a.verified, a.from_user)
                 for a in Attendee.objects.filter(event=event)]

and then:

{% for attendee, verified, from_user in attendees_list %}

You can then control what each says at the template level using {% if verified %} or {% if from_user %} blocks.

Alternatively, you can just do:

attendees = Attendee.objects.filter(event=event)

and refer to attendee.profile, attendee.verified, and attendee.from_user directly in the template.