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Home/ Questions/Q 6834157
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:04:36+00:00 2026-05-26T23:04:36+00:00

I have an class that implements an interface. I’d like to examine only the

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I have an class that implements an interface. I’d like to examine only the property values that implement my interface.

So, let’s say for example I have this interface:

public interface IFooBar {
    string foo { get; set; }
    string bar { get; set; }
}

And this class:

public class MyClass :IFooBar {
    public string foo { get; set; }
    public string bar { get; set; }
    public int MyOtherPropery1 { get; set; }
    public string MyOtherProperty2 { get; set; }
}

So, I need to accomplish this, without the magic strings:

var myClassInstance = new MyClass();
foreach (var pi in myClassInstance.GetType().GetProperties()) {
    if(pi.Name == "MyOtherPropery1" || pi.Name == "MyOtherPropery2") {
        continue; //Not interested in these property values
    }
    //We do work here with the values we want. 

}

How can I replace this:

if(pi.Name == 'MyOtherPropery1' || pi.Name == 'MyOtherPropery2') 

Instead of checking to see if my property name is == to a magic string, I’d like to simply check to see if the property is implemented from my interface.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:04:36+00:00Added an answer on May 26, 2026 at 11:04 pm

    Why use reflection if you know the interface ahead of time? Why not just test if it implements the interface then cast to that?

    var myClassInstance = new MyClass();
    var interfaceImplementation = myClassInstance as IFooBar
    
    if(interfaceImplementation != null)
    {
        //implements interface
        interfaceImplementation.foo ...
    }
    

    If you really must use reflection, get the properties on the interface type, so use this line to get properties:

    foreach (var pi in typeof(IFooBar).GetProperties()) {
    
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