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Home/ Questions/Q 8705703
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:25:51+00:00 2026-06-13T03:25:51+00:00

I have an entity (Request) which is partitioned by userId. For each userId, I

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I have an entity (Request) which is partitioned by userId. For each userId, I will have an index, right?

However, I would like to quickly search the request by userId. Is there a simple way to do that? Or I will need to choose another field to create the partition?

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:25:53+00:00Added an answer on June 13, 2026 at 3:25 am

    You can partition TWO ways if you like. Let’s say you do this

    public class Request {
        @NoSqlId
        @NoSqlIndexed
        private String uniqueId;
    
        @NoSqlIndexed
        @NoSqlPartitionedBy
        @NoSqlManyToOne
        private User user;
    
        @NoSqlIndexed
        @NoSqlPartitionedBy
        private LocalDate beginningOfEachMonth;
    }
    

    You can have private String userId instead of User if you like ;).

    Now, you can query into a time partition using the beginning of the month as a key and just do a query OR you can query into a user partition using user as the key.

    Your named query IF you partition by two things would be…

    query="PARTITIONS("user", :user) SELECT r FROM TABLE as r"
    

    If you only partition your table by users, you can write

    query="PARTITIONS(:user) SELECT r FROM TABLE as r"
    

    NOTE: The only reason you sometimes need to index the primary key like I have is for a range query on the primary key….for an equals query where pk= some value, you don’t need an index obviously since you can look up by the primary key itself.

    Dean

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