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Home/ Questions/Q 7806577
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T02:34:50+00:00 2026-06-02T02:34:50+00:00

I have an entry in my urls.py that acts as a catch-all which loads

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I have an entry in my urls.py that acts as a catch-all which loads a simple view if it finds an appropriate page in the database. The problem with this approach is that the URL solver will then never fail, meaning that the APPEND_SLASH functionality won’t kick in – which I need.

I’d rather not have to resort to adding a prefix to the static page URLs to stop it being a catch-all. I do know about flatpages, which uses a 404 hook rather than an entry in urls.py, and I had kinda hoped to avoid having to use it, but I guess this problem might be exactly the kind of reason why one would use it.

Any way round this problem or should I just give in and use flatpages?

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  1. Editorial Team
    Editorial Team
    2026-06-02T02:34:52+00:00Added an answer on June 2, 2026 at 2:34 am

    Make sure that your catch-all URL pattern has a slash at the end, and that the pattern is the last in your URLconf. If the catch-all pattern doesn’t end with a slash, then it will match stray URLs before the middleware tries appending a slash.

    For example, use r'^.*/$' instead of r'^.*' as your last pattern.

    To do the same, but pass the url to the view as a named argument, use r'^(?P<url>.*)/$'.

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