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Home/ Questions/Q 990521
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:57:31+00:00 2026-05-16T05:57:31+00:00

I have an enumeration in scala mapped to strings in JPA. For more comfortable

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I have an enumeration in scala mapped to strings in JPA. For more comfortable coding, I defined implicit conversions between them. So I now can define value val person.role = "User", – person.role is the enumeration type "User" a String so there’s the conversion. But when I try to compare these two, I always get false, because the def equals (arg0: Any) : Boolean takes Any so there’s not any conversion triggered. I need some explicit conversion, but my plan was to be able to omit that, what do you think is the best practice | neatest solution here?

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:57:32+00:00Added an answer on May 16, 2026 at 5:57 am

    The Value("User") in your Enumeration is of type Val. And I believe it’s implementation of equals does not compare the string name of the value. I think one heavy handed way of doing this is creating your own Enumeration and Val so that it returns true if the name match.

    But in my code uses, not with JPA, I always convert the string into the MyEnumeration.Value. This is easy with things like:

     object E extends Enumeration { val User = Value("User") }
    
     scala> val a = E.withName("User")
     a: E.Value = User
    

    Note that when using withName, if the string does not match any name in the enumeration you get an exception.

    Then always use the enumeration fields in your comparisons:

    scala> a == E.User
    res9: Boolean = true
    

    If JPA only returns a string, and there is no way around it. Then I think the best option is to either convert the value to string and match string to string, or upgrade the string to a Val and compare Val. Mixing these types will not work for comparison, unless you you implement some kind of extension to the equals method, and that is tricky.

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