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Home/ Questions/Q 7993433
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:50:56+00:00 2026-06-04T13:50:56+00:00

I have an example: Assembly asm = Assembly.Load(ClassLibrary1); Type ob = asm.GetType(ClassLibrary1.UserControl1); UserControl uc

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I have an example:

        Assembly asm = Assembly.Load("ClassLibrary1");
        Type ob = asm.GetType("ClassLibrary1.UserControl1");
        UserControl uc = (UserControl)Activator.CreateInstance(ob);
        grd.Children.Add(uc);

There I’m creating an instance of a class, but how can I create an instance of a class which implements some interface? i.e. UserControl1 implements ILoad interface.

U: I can cast object to interface later, but I don’t know which type in the assemblies implements the interface.

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:50:58+00:00Added an answer on June 4, 2026 at 1:50 pm

    This is some code i have used a few times. It finds all types in an assembly that implement a certain interface:

    Type[] iLoadTypes = (from t in Assembly.Load("ClassLibrary1").GetExportedTypes()
                         where !t.IsInterface && !t.IsAbstract
                         where typeof(ILoad).IsAssignableFrom(t)
                         select t).ToArray();
    

    Then you have all types in ClassLibrary1 that implement ILoad.

    You could then instantiate all of them:

    ILoad[] instantiatedTypes = 
        iLoadTypes.Select(t => (ILoad)Activator.CreateInstance(t)).ToArray();
    
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