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Asked: 2026-06-06T18:43:05+00:00

I have an excel file and I want to read each column and create

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I have an excel file and I want to read each column and create separate lists for them. I want to then compare each element of each list with other corresponding lists I have.
Is there a way I can convert the columns into lists using python?

for eg(i can get this file as a txt space separated file or an excel file)

HST_9578_02_ACS_WFC_F775W 245.8976441 -26.5255957 4339.570 1882.364
HST_10615_03_ACS_WFC_F435W 245.8976450 -26.5255138 2084.978 2101.122
HST_10120_02_ACS_WFC_F658N 245.8976758 -26.5255024 1778.055 1752.193
HST_10775_64_ACS_WFC_F606W 245.8977532 -26.5255296 2586.612 2603.519
HST_10775_64_ACS_WFC_F814W 245.8977532 -26.5255296 2586.612 2603.519
HST_9578_02_ACS_WFC_F775W 245.8978148 -26.5255491 4328.571 1885.712
HST_10120_02_ACS_WFC_F625W 245.8978053 -26.5254741 1769.711 1754.229
HST_10353_02_ACS_WFC_F435W 245.8976003 -26.5257784 3758.430 985.125
HST_10775_64_ACS_WFC_F606W 245.8979115 -26.5254936 2576.410 2606.114
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1 Answer

  1. Editorial Team

    This sounds like a job for Python’s CSV module. Each row read is returned as a list of strings.

    To borrow a short example from the documentation:

    Each row read from the csv file is returned as a list of strings. No
    automatic data type conversion is performed.

    A short usage example:

    [this simply prints out each row]

    import csv
with open('some.csv', 'rb') as f:
    reader = csv.reader(f)
    for row in reader:
        print row

    You could get to specific columns by indexing into the rows with the index values as appropriate.

    Or if you want to do this “manually” (each row is separated by a ,):

    s = """HST_9578_02_ACS_WFC_F775W 245.8976441 -26.5255957 4339.570 1882.364,
HST_10615_03_ACS_WFC_F435W 245.8976450 -26.5255138 2084.978 2101.122,
HST_10120_02_ACS_WFC_F658N 245.8976758 -26.5255024 1778.055 1752.193,
HST_10775_64_ACS_WFC_F606W 245.8977532 -26.5255296 2586.612 2603.519,
HST_10775_64_ACS_WFC_F814W 245.8977532 -26.5255296 2586.612 2603.519,
HST_9578_02_ACS_WFC_F775W 245.8978148 -26.5255491 4328.571 1885.712,
HST_10120_02_ACS_WFC_F625W 245.8978053 -26.5254741 1769.711 1754.229,
HST_10353_02_ACS_WFC_F435W 245.8976003 -26.5257784 3758.430 985.125,
HST_10775_64_ACS_WFC_F606W 245.8979115 -26.5254936 2576.410 2606.114
"""

bl = [[],[],[],[],[]]
for r in s.split(','):
    for c in range(5):
        bl[c].append(r.split()[c])

    gives:

    bl[0]
['HST_9578_02_ACS_WFC_F775W', 'HST_10615_03_ACS_WFC_F435W', 'HST_10120_02_ACS_WFC_F658N', 'HST_10775_64_ACS_WFC_F606W', 'HST_10775_64_ACS_WFC_F814W', 'HST_9578_02_ACS_WFC_F775W', 'HST_10120_02_ACS_WFC_F625W', 'HST_10353_02_ACS_WFC_F435W', 'HST_10775_64_ACS_WFC_F606W']

bl[1]
['245.8976441', '245.897645', '245.8976758', '245.8977532', '245.8977532', '245.8978148', '245.8978053', '245.8976003', '245.8979115']

bl[2]
['-26.5255957', '-26.5255138', '-26.5255024', '-26.5255296', '-26.5255296', '-26.5255491', '-26.5254741', '-26.5257784', '-26.5254936']

bl[3]
['4339.57', '2084.978', '1778.055', '2586.612', '2586.612', '4328.571', '1769.711', '3758.43', '2576.41']

bl[4]
['1882.364', '2101.122', '1752.193', '2603.519', '2603.519', '1885.712', '1754.229', '985.125', '2606.114']

    EDIT/UPDATE:

    To combine the two approaches into one:

    import csv

with open('so.csv') as f:
    bl = [[],[],[],[],[]]
    reader = csv.reader(f)
    for row in reader:
        for col in range(5):
            bl[col].append(row[col])

    The advantage of using with to open the file is that it will be automatically closed for you when you are done or if an exception occurs.

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