Question

I have an HTML file and i want to convert to XML document only using XSLT..

I want:

1. All the nodes to be retained.
2. And all elements are sorted.
3. And code should be in dynamically.
4. i have an comma(,)between the elements so i need to handle that as delimiter like <dl>,</dl> as where it comes..(not only comma some speces also want to retained)

i have an huge file so i want an simple code to process all the html nodes.here i explained my codeing with the xslt
if u understand it plz help me..

My HTML file is..

<span id="2102" class="one_biblio">
<span id="2103" class="one_section-title"><b>Title</b></span>
<span id="2204" class="one_authors">
    <span id="2205" class="one_author">, <!--here the comma arraives-->

        <!-- here the id value misplaced -->
        <span id="2207" class="one_surname">Surname</span>,<!--here the comma arraives-->
        <span id="2206" class="one_given-name">GivenName</span>,<!--here the comma arraives-->
  </span>
</span>
<span id="2208" class="one_title">
    <span id="2209" class="one_maintitle">technology</span>
</span>

And i want the Output XML file as:
Here the attribute class value is used as element name.
And the elements to be sorted.
And the comma(,) should be come within the delimiter tag.

  <biblio id="2102" >
    <section-title id="2103" ><b>Title</b></section-title>
                <authors id="2204" >
                        <author id="2205" >
                            <dl>,</dl>  <!--here i want like this-->
                            <!-- correrct the id -->
                            <given-name id="2206" >GivenName </given-name><dl>,</dl><!--here i want like this-->
                            <surname id="2207" >Surname</surname><dl>,</dl><!--here i want like this-->
                        </author>
                    </authors>
                    <title id="2208" >
                        <maintitle id="2209" >technology</maintitle>
                    </title>             
          </biblio>

The XSLT i wrote is ..

 <xsl:template match="*[@class]">   
    <xsl:element name="{substring-after(@class, 'mps_')}">
        <xsl:copy-of select="@*[not(name()='class')]"/>
        <xsl:if test="not(current())">
        <xsl:apply-templates>    
                            <xsl:sort select="@id" data-type="number"/>   
        </xsl:apply-templates>   
        </xsl:if>
    </xsl:element>
</xsl:template> 

Help me.......

Answer 1

This XSLT 1.0 transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext">
     <xsl:output omit-xml-declaration="yes" indent="yes"/>
     <xsl:strip-space elements="*"/>

     <xsl:variable name="vrtfPass1">
       <xsl:apply-templates select="/*"/>
     </xsl:variable>

     <xsl:template match="node()|@*">
         <xsl:copy>
           <xsl:apply-templates select="node()|@*"/>
         </xsl:copy>
     </xsl:template>

     <xsl:template match="node()|@*" mode="pass2">
         <xsl:copy>
           <xsl:apply-templates select="node()|@*"/>
         </xsl:copy>
     </xsl:template>

     <xsl:template match="/">
      <xsl:apply-templates mode="pass2"
           select="ext:node-set($vrtfPass1)/*"/>
     </xsl:template>

     <xsl:template match="*[@class]" mode="pass2">
      <xsl:element name="{substring-after(@class, 'one_')}">
       <xsl:copy-of select="@*[not(name()='class')]"/>
       <xsl:apply-templates>
         <xsl:sort select="@id" data-type="number"/>
       </xsl:apply-templates>
      </xsl:element>
     </xsl:template>

     <xsl:template match=
      "text()
        [../self::span[@class]
        or
         preceding-sibling::node()[1]
                            [self::span[@class]]
         ]
           [contains(., ',')]">
        <xsl:value-of select="substring-before(., ',')"/>
        <dl>,</dl>
        <xsl:value-of select="substring-after(., ',')"/>
      </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document (corrected to be made well-formed !!!):

<span id="2102" class="one_biblio">
    <span id="2103" class="one_section-title">
        <b>Title</b>
    </span>
    <span id="2204" class="one_authors">
        <span id="2205" class="one_author">, 
            <span id="2207" class="one_surname">Surname</span>,
            <span id="2206" class="one_given-name">GivenName</span>,
        </span>
    </span>
    <span id="2208" class="one_title">
        <span id="2209" class="one_maintitle">technology</span>
    </span>
</span>

produces the wanted, correct result:

<biblio id="2102">
   <span id="2103" class="one_section-title">
      <b>Title</b>
   </span>
   <span id="2204" class="one_authors">
      <span id="2205" class="one_author">
         <dl>,</dl> 

         <span id="2207" class="one_surname">Surname</span>
         <dl>,</dl>

         <span id="2206" class="one_given-name">GivenName</span>
         <dl>,</dl>

      </span>
   </span>
   <span id="2208" class="one_title">
      <span id="2209" class="one_maintitle">technology</span>
   </span>
</biblio>

Explanation: Two-pass transformation. The first pass fixes the comma, the second pass does the rest of the processing.