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Home/ Questions/Q 7511717
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T23:38:17+00:00 2026-05-29T23:38:17+00:00

I have an HTML image element as shown below: var actionImage = $(<img></img>); actionImage.attr(id,

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I have an HTML image element as shown below:

var actionImage = $("<img></img>");
    actionImage.attr("id", getRandomString()); 
    actionImage.attr("width", "16").attr("height", "16").attr("src", "Action_normal.png");
    actionImage.attr("style", "cursor: hand;");
    actionImage.bind('mouseover', function() {
        OnMouseOver($(this).get(0));              
    });

When I clone this element I loose the mouseover event. How can I make sure that the events are also cloned.

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  1. Editorial Team
    Editorial Team
    2026-05-29T23:38:20+00:00Added an answer on May 29, 2026 at 11:38 pm

    Clone takes a boolean parameter that, when it’s true (which isn’t the default), conserves data and events. You want $actionImage.clone(true).

    And as @Purmou mentions, you could also do this by binding your JS events via on or delegate, to avoid this very problem.

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