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Editorial Team
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Asked: 2026-05-26T00:48:14+00:00

I have an html page called test.html, here is it’s content: <!DOCTYPE html PUBLIC

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I have an html page called test.html, here is it’s content:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head>
    <title></title> </head> <body style="margin: 0; padding: 0; background: #d9d9d9;">
    <form name="form1" method="post" action="NewsLetterPreview.aspx?NewsletterID=1" id="form1">
    <div>
        <input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwUKMTA3NzM3OTc4N2Rkkk3StA9iwyEdCoR43JPpw6OyRHubNTnbXatTbxCXsVA=" />
    </div>
    </form> </body> </html>

I then have another page which I am using $.get to get the content of the page:

$.get("test.html", function (data) {
            alert($(data).find("body").html());
        });

However the alert($(data).find("body").html()) returns null. It does the same for the alert($(data).find("form").html()) also. Only if I specify alert($(data).find("div").html()) does it return the input field.

How can I select the body / form?

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1 Answer

  1. Editorial Team

    If you want to replace your body with fetched HTML, this should do it.

    $.get("test.html", function (data) {
            $(body).html(data);
        });

    EDIT:

    Missread your question.

    It’d suggest you to use json or .replace() instead.

    Example: alert(data.replace(/^.*?\<body\>(.*?)\<\/body\>.*$/, "$1"));

    If you want body tags included: alert(data.replace(/^.*?(\<body\>.*?\<\/body\>).*$/, "$1"));

    I don’t think jquery can work with HTML the way you wish. Either include it in the code and then use regular functions or find another workaround.

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