Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9260461
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 18, 20262026-06-18T12:53:53+00:00 2026-06-18T12:53:53+00:00

I have an image in a folder, when I try to set the ImageUrl

  • 0

I have an image in a folder, when I try to set the ImageUrl from the behind code I get a little symbol that looks broken in half instead of the picture. If I set the ImageUrl in the Image properties it works. What am I doing wrong?

var imagepath = Server.MapPath(@"~/images/candidates/small/image.jpg");
System.Drawing.Image image = System.Drawing.Image.FromFile(imagepath);
int ActualWidth = image.Width;
int ActualHeight = image.Height;
candImage.ImageUrl = imagepath;
candImage.Height = ActualHeight;
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-18T12:53:54+00:00Added an answer on June 18, 2026 at 12:53 pm

    The ImageUrl should be the URL to the image, as you would get it from a browser, not its location on the hard drive, which is what Server.MapPath returns.

    You should be using:

    candImage.ImageUrl = @"~/images/candidates/small/image.jpg";
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a single image file in a folder in my Eclipse project that
In my code below it seems that the image does not get uploaded when
I have a image folder which contains sub directory for each album of images
I have put 4 image for each folder mdpi,ldpi,hdpi,xdpi in the ratio of 3:4:6:8.
I have a folder called Etc which has an image I want to use
i have following coding to resize image and than save it my virtual folder
I have use these code to upload two images in folder of the root
I have a bunch of images in a folder that are effectively just pieces
I am creating an applescript that creates a backup image of the /Users folder
I have a web page that has a Folder Picker pop up. It allows

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.