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Home/ Questions/Q 967537
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:20:03+00:00 2026-05-16T02:20:03+00:00

I have an inclusion pattern as follows: /* * Class1.h */ #ifndef CLASS1_H_ #define

  • 0

I have an inclusion pattern as follows:

/*
 * Class1.h
 */

#ifndef CLASS1_H_
#define CLASS1_H_

#include "Class2.h"

namespace Class1_namespace
{

class Class1
{
  Class2* Class2_ptr;
  void Class1_member()
  {
      (*Class2_ptr).Class2_method();
  }
};

}

#endif /* CLASS1_H_ */

/*
 * Class2.h
 */

#ifndef CLASS2_H_
#define CLASS2_H_

#include "Class1.h"

class Class2
{
    Class1_namespace::Class1 Class2_data;

public:
    void Class2_method(){};
};

#endif /* CLASS2_H_ */

/*
 * main.cpp
 */

#include "Class1.h"

int main()
{
    return 0;
}

However, this leads to the error “’Class1_namespace’ does not name a type.”

Is this error caused by the ordering of my inclusions?

What are some possible solutions? I’m dubious about forward declarations solving my problem.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:20:03+00:00Added an answer on May 16, 2026 at 2:20 am

    Class1 doesn’t need to include Class2.

    When you have mutual dependency (which you don’t — you could just not include 2 in 1), you can usually solve it by using forward declarations instead of inclusions.

    For example, let’s say that Class1 looked like this

    #include "Class2.h"
    
    namespace Class1_namespace
    {
    
        class Class1
        {
            Class2* class2;
        };
    
    }
    

    Where you think you need the include, you could instead do this:

    class Class2;
    
    namespace Class1_namespace
    {
    
        class Class1
        {
            Class2* class2;
        };
    
    }
    

    to break the mutual inclusion.

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