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Home/ Questions/Q 6337611
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T19:17:03+00:00 2026-05-24T19:17:03+00:00

I have an input form for a sample php. <form action=insert.php method=post> <table> <tr>

  • 0

I have an input form for a sample php.

<form action="insert.php" method="post">
        <table>
            <tr>
                <td>First Name:</td>
                <td><input type="text" id="fname" name="fname" /></td>
            </tr>
            <tr>
                <td>Last Name:</td>
                <td><input type="text" id="lname" name="lname" /></td>
            </tr>
            <tr>
                <td>Age:</td>
                <td><input type="text" id="age" name="age" /></td>
            </tr>
            <tr>
                <td>&nbsp;</td>
                <td><input type="submit" value="Add Person!" /></td>
            </tr>
        </table>
    </form>

and the insert.php goes like this

<?php
    $host = "localhost";
    $user = "root";
    $pass = "";
    $con = mysql_connect($host, $user, $pass);
    $db = "phptest";    

    if(!$con)
    {
        die("Could not connect: " . mysql_error());
    }
    mysql_select_db($db,$con);
    $sql = "INSERT INTO persons (FirstName,LastName,Age) VALUES ('$_POST[fname]','$_POST[lname]','$_POST[age]')";
    mysql_query($sql,$con);
    mysql_close($con);
?>

It works fine for the first input. When I input another values and press the submit button, the data is not saving into the database. In the database, it only shows 1 row filled with my first input. What’s the problem on the code for insert.php? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T19:17:03+00:00Added an answer on May 24, 2026 at 7:17 pm

    Please also do

    echo mysql_error();
    

    right after mysql_query() to know if something is wrong, although your query seems pretty fine.

    Also, posting your table structure might help. *It might be that you forgot to have an id in your table that is set to primary_key and auto_increment*

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