Question

I have an intent filter that looks like so:

<activity
    android:name="com.test.Call"
    android:label="@string/makeCall" >
    <intent-filter>
        <action android:name="android.intent.action.CALL" />
        <category android:name="android.intent.category.DEFAULT" />
        <action android:name="android.intent.action.CALL_PRIVILEGED" />
        <data android:scheme="tel" />
    </intent-filter>
</activity>

This works fine and when you try to make a call my text appears as one of the options. What I want to do is process the number being called and ask the user some questions and then continue on with the call. I do this by running the following code after I do whatever processing I have do do:

Uri phoneCall = Uri.parse("tel:"  + numToCall);
Intent caller = new Intent(Intent.ACTION_DIAL, phoneCall);
startActivity(caller);

The issue is, it is displaying the same options from the beginning again (the native caller and my intent filter). This is not what I want, I want to bypass my intent filter and go directly to the native caller. Is there a way to do this? How can I force the intent to go directly to the native caller? I am looking at moving this to a broadcast receiver but would rather go this route.

Thanks

Answer 1

You could try disabling your component via PackageManager.setComponentEnabledSetting() [use the DONT_KILL_APP flags!], but you’ll need to re-enable the component again before the next call.

Or you could take Huang’s comment above but find out components that catch the ACTION_CALL intent and build your own chooser if there’s more than one other than you – use PackageManager.queryIntentActivities() to get a list of Activities.

Using the broadcast is really the right way to go.