Question

I have an interactive form system that has different modules, where the forms for each module is contained inside a different div element. When i change from one module to another, I often do this:

$('#module_1').hide();
$('#module_2').fadeIn();

I like this, but now, after developing this system for some time, I have some functions (like re-initialize a jqgrid) that I want to happen every time a fadeIn occurs. I set up this up like this:

$('#module_2').bind('fadeIn',function(){
    initialize_jqgrid();
});

Is there a way I can make this work for all instances of $('#module_2').fadeIn(); without having to go to every instance and replace it with this?

$('#module_2').fadeIn().trigger('fadeIn');

The motivation behind this is just to have cleaner code, $('#module_2').fadeIn().trigger('fadeIn'); is a little redundant.

Thanks a lot!

Answer 1

Sure,

var _old = $.fn.fadeIn;

$.fn.fadeIn = function(){
    var self = this;
    return _old.apply(this,arguments).promise().done(function(){
        self.trigger("fadeIn");
    });
};

// and your code: // replace .bind with .on if jQuery 1.7+
​$("div").bind("fadeIn",function(){alert("worky");});

$("div").fadeIn(2000);​​​​​​​​​​​​​​​​​

Demo
http://jsfiddle.net/gEVsX/2/

Update for comment

var _old = $.fn.fadeIn;

$.fn.fadeIn = function(){
    return _old.apply(this,arguments).trigger("fadeIn");
};

// and your code: // replace .bind with .on if jQuery 1.7+
​$("div").bind("fadeIn",function(){alert("worky");});

$("div").fadeIn(2000);​​​​​​​​​​​​​​​​​