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Home/ Questions/Q 6936103
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:11:27+00:00 2026-05-27T12:11:27+00:00

I have an Interface [a] and a Implementer class [b]. [b] have its own

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I have an Interface [a] and a Implementer class [b]. [b] have its own methods apart of the implemented ones.

//-----------
public interface a
{
void functionA();
}
//-----------

public class b:a
{
void functionA(){}
void functionB(){}

}
//------------

In project X inside the solution. When I code: [project is a class library]

a test = new b();
test.functionB(); //It Works

In another project with a references to the library [Console application]

a test = new b();
test.functionB(); //Error CS1061 --> a doesn't have a method called function b

Sorry but names are in spanish. Interface: pastebin.com/Unm5Adkd, Implementer: pastebin.com/wmikck9H, Program: Console app: pastebin.com/Yus91hQL… Thanks everyone for your help. 😛

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:11:28+00:00Added an answer on May 27, 2026 at 12:11 pm

    I assume that you are asking why you are getting the CS1061 error.

    It’s simple. In your console application even though you instantiate an object of type ‘b’ (“new b()”) you appear to assign it to a variable referring to something that is an ‘a’. The interface ‘a’ according to your sample does indeed not contain a method called ‘functionB()’.

    You have two options in this case.

    Option one is adding method ‘functionB()’ to the interface definition as well:

    public interface a {
       void functionA(){}
       void functionB(){}
    }
    

    Option two is making sure that variable ‘a’ in your console application is of type ‘b’:

    b a = new b();
    a.functionB();
    

    On a side note I would suggest to stick with generally accepted naming guidelines, e.g. starting with uppercase letters for names of classes and methods.

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