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Home/ Questions/Q 6021723
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:45:18+00:00 2026-05-23T03:45:18+00:00

I have an interface: public interface InterfaceA<S,T>{} and I want to load an instance

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I have an interface:

public interface InterfaceA<S,T>{}

and I want to load an instance of all classes that implement this interface, regardless of the generic parameters S and T. So I have a class with a method to do this. The method signature is currently:

public IEnumerable<object> GetInstancesOfImplementingTypes (Type targetType)

to reflect through the loaded assemblies looking for types that have a GetGenericTypeDefinition equal to the GetGenericTypeDefinition of the targetType. I’m using the type (rather than having a T param on the method) so that I don’t have to specify the generic arguments, ie I can call it like so:

var foundinstances = o.GetInstancesOfImplementingTypes(typeof(InterfaceA<,>))

But I seem to have to return the instances of the found types as objects. is there some way that I can return a more constrained type than just object, as I know all the instances will be some implementation of InterfaceA, I just don’t know what S and T will be.

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:45:19+00:00Added an answer on May 23, 2026 at 3:45 am

    No. Different instantiations of InterfaceA<S,T> are unrelated as far as the CLR is concerned, so unless they have a non-generic common base you must use object.

    If there are some members in InterfaceA that don’t depend on the type arguments and that you wish to access irregardless of S and T, you may wish to create another non-generic interface that InterfaceA inherits from containing only those members.

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