Question

I have an interface with two methods

interface IFoo{
  void FooOne(A,B,C);
  void FooTwo(D,E,F);
}

Now there are two implementation class which extends this interface. One is as follows:

class Foo1 implements IFoo{
 void FooOne(A,B,C);
  void FooTwo(D,E,F);
} 

Other one is as follows :

 class Foo2 implements IFoo{
  void FooOne(A,B,C);
  void FooTwo(D,E,F);
} 

Now Foo2 class dosen’t needs parameter E at all. Parameter E is only required for class FOO1. So it’s somehow ambious why this parameter is passed to class Foo2. So is there some another way so that I can do something like for class Foo2.

 class Foo2 implements IFoo{
  void FooOne(A,B,C);
  void FooTwo(D,F);
} 

Answer 1

If FooTwo(D,E,F) is your interface, then class Foo2 must implement that.

However, you could expose another non-interface overloaded public method for Foo2, like this

public void FooTwo(D,F) {
  this(D, null, F);
}