Question

I have an iPhone app which gets a response from a php file. This response generates an html file where the body contains a json object. How do I retrieve this JSON object ?

$query = "SELECT username FROM userData WHERE username = '$username'";  
    $result = mysql_query($query);  
    if (mysql_num_rows($result) > 0) { 
        sendResponse(200, json_encode('SUCCESS Notification'));
    } else { 
    $query = "INSERT INTO userData (username,password,email,signup_date) VALUES ('$username','$password','$email','$date')";
    $result=mysql_query($query,$connection) or die (mysql_error()." Kann Tabelle der Datenbank nicht lesen!");
    }  

    function sendResponse ($status = 200, $body ='', $content_type = 'application/json'){
            $status_header = 'HTTP/1.1 ' . $status . ' ' . 'OK';
            header($status_header);
            header('Content-type:' . $content_type);
            echo $body;
        }

This is what happens in my iphone app:

 NSURLResponse *theResponse =[[NSURLResponse alloc]init];
        NSError *error;
        NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&error];      

         NSDictionary *jsonDictionaryResponse =[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
        NSLog(@"json response = %@", jsonDictionaryResponse);

Answer 1

As far as I can see, you don’t add HTML-Tags around your JSON enocded string. So you could just parse the whole response body. I recommend you using jQuery (if your don’t do already) or the JSON library.

But please note, that you should chage your MIME-Type to application/json when sending JSON data and that it doesn’t make sense to json_encode a string.

sendResponse(200, json_encode(array('SUCCESS Notification')), 'application/json');