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Home/ Questions/Q 6731773
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:34:07+00:00 2026-05-26T10:34:07+00:00

I have an issue where I have something like this: class Thing(models.Model): def can_vote(self,

  • 0

I have an issue where I have something like this:

class Thing(models.Model):
    def can_vote(self, user):
        if self.vote_set.filter(user=user).count() < 2:
            return True
        # (A pile of other conditions)

class SomeUser(models.Model):
    pass

class Vote(models.Model):
    user = models.ForeignKey(SomeUser)
    things = models.ForeignKey(Thing)

and I want to do this in a template:

{% if thing.can_vote %}
   {# Review stuff #}
{% endif %}

Depending on if the current user has voted less than the amount of times or not. The issue seem to be that Django doesn’t allow you to pass parameters to the method. Is there a way for me to accomplish this neatly?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:34:08+00:00Added an answer on May 26, 2026 at 10:34 am

    You can use custom template tag or filter. If filter:

    @register.filter
    def can_vote_on(user, thing):
        if thing.vote_set.filter(user=user).count() < 2:
            return True
        # (A pile of other conditions)
    

    In template:

    {% if user|can_vote_on:thing %}
       {# Review stuff #}
    {% endif %}
    
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