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Home/ Questions/Q 7958237
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:23:24+00:00 2026-06-04T04:23:24+00:00

I have an List which is filled with ints, like this: [0] 1 [1]

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I have an List which is filled with ints, like this:

[0] 1
[1] 4
[2] 4
[3] 8
[4] 9
[5] 1
[6] 1

So basically random numbers in there, but the same number can occure multiple times in that list.

What i want is to group them by number, but that i can also tell how many times that number was in the list. So that i have a something like:

[0] 
  [number] 1
  [total] 3  // Occured 3 times in the list
[1]
  [number] 4
  [total] 2
[2]
  [number] 8
  [total] 1
[3]
  [number] 9
  [total] 1

Is there a fast/easy way to accomplish this? Or do i have the write out all sorts of loops and checks to construct something like this manually?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T04:23:24+00:00Added an answer on June 4, 2026 at 4:23 am

    Use GroupBy and Count:

    var numberGroups = numbers.GroupBy(i => i);
    foreach(var grp in numberGroups)
    {
        var number = grp.Key;
        var total  = grp.Count();
    }
    

    Here’s another example which uses an anonymous type to store some informations. It also creates an array since it seems to be the desired result:

    var numberGroups = numbers.GroupBy(i => i)
                       .Select(grp => new{
                           number  = grp.Key,
                           total   = grp.Count(),
                           average = grp.Average(),
                           minimum = grp.Min(),
                           maximum = grp.Max()
                       })
                       .ToArray();
    
    foreach (var numInfo in numberGroups)
    {
        var number = numInfo.number;
        // ...
        var maximum = numInfo.maximum;
    }
    
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